/StepsCalculation

实现一个函数，对一个正整数n，算得到1需要的最少操作次数。操作规则为：如果n为偶数，将其除以2；如果n为奇数，可以加1或减1；一直处理下去

WARNING:

stepCount.c has a fetal logic error, we can't get correct answer through this program.

steps.txt is correct answers to the integers in Numbers.txt
steps.1.txt is the result of stepCount.c
You can see the differences between these results.