you can refer readmes of
- LinkedList
Corner cases- empty LL
- LL with one node
- Arrays
for every array quest, you should ask the interviewer if not already specified:- is the array sorted?
- minimum no of elements in array?
- does the array contain negative elements
Corner cases - would the code run properly if n=1?
- Matrix
- Sorting
- Stack
- Queue
- Hashing
- Dynamic Programming
- Graph
Corner cases- would the dfs code run properly for 1x1 matrix?
- Interview prep
- Trees and graph
- Trie
-
Cheatsheet for time and space complexity: https://www.bigocheatsheet.com/
-
The below tips are taken from here
If input array is sorted then
- Binary search
- Two pointers
If asked for all permutations/subsets then
- Backtracking
If given a tree then
- DFS
- BFS
If given a graph then
- DFS
- BFS
If given a linked list then
- Two pointers
If recursion is banned then
- Stack
If must solve in-place then
- Swap corresponding values
- Store one or more different values in the same pointer
If asked for maximum/minumum subarray/subset/options then
- Dynamic programming
If asked for top/least K items then
- Heap
If asked for common strings then
- Map
- Trie
Else
- Map/Set for O(1) time & O(n) space
- Sort input for O(nlogn) time and O(1) space
Operation | Unsorted Arr | Sorted Arr | Linked List | BST(Balanced) | Hash Table |
---|---|---|---|---|---|
Search | O(n) | O(logn) | O(n) | O(logn) | O(1) |
Insert | O(1) | O(n) | O(1) for sorted LL: O(n) |
O(logn) | O(1) |
Delete | O(n) | O(n) | O(n) | O(logn) | O(1) |
Get Closest value | O(n) | O(logn) | O(n) | O(logn) | O(1) |
Sorted Traversal | O(nlogn) | O(n) | O(nlogn)/ O(n) for sorted LL | O(n) | O(nlogn) |
- Here sorted traversal implies printing items in sorted order
- upto n<=10^3 naive sols will work most of the times
n-value | Maximum time it can take |
---|---|
n <= 12 | O(n!) |
n <= 25 | O(2^n) |
n <= 100 | O(n^4) |
n <= 500 | O(n^3) |
n <= 10^4 | O(n^2) |
n <= 10^6 | O(nlogn) - sorting |
n <= 10^8 | O(n) - hashing |
n > 10^8 | O(logn) or O(1) - binary search |