Generate random number in c++
Normal Distribution Model // Gaussian Distribution
No Repeat Integer Model // from 0 to n-1 integer
Meanly Distribution Model // from min to max
Probility Random Model // meanly distribution from 0 to 1
//Most of time,the third parameter(seed) should be set to true, unless you want a changeless sequence.
NormalRandomGenerator(double mean, double variance, bool seed = true);
//Very easy to use
MeanlyRandomGenerator(double min, double max);
//No need any parameter.
ProbilityRandomGenerator(void);
//Get no repeat integer number from 0 to n-1 and it's time complexity is O(max) ;
NoRepeatIntRandomGenerator(int max);
Using .getOne() or operator >> will gain a number. Two functions have no difference.
Below RG is one of random model instance ;
double d = RG.getOne();
RG >> d;
int a, b, c;
RG >> a >> b >> c;If you are not sure which kinds of random model will be used until the program runs, you can refer the tutorial below.
Or the third part of test.cpp
RandomModel *ranGen;
if ( /* use Normal Distribution Model */) ranGen = new NormalRandomGenerator(20, 10);
else if (/* use Meanly Distuibution Model */ ) ranGen = new MeanlyRandomGenerator(10, 20);
double temp = ranGen->getOne();If you want really random number, you should use random seed such as srand((unsigned int)time(NULL));
When constructing a Normal Distribution Model, you will not gain really random number if the third parameter is false no matter have you used random seed.