A C++ linear system solver
Defines a class called Vector. Vector is exatly the same as std::vector, but with some Operator Overloads.
Allows Vector to be printed in std::cout
Vector<int> vector {1,2,3};
std::cout << vector << "\n";will print
{1,2,3}Adds two Vector
Vector<int> vector1 {1,2,3}, vector2 {4,5,6}, vectorSum;
vectorSum = vector1+vector2;
std::cout << vectorSum << "\n";will print
{5,7,9}Subtracts two Vector
Vector<int> vector1 {1,2,3}, vector2 {4,5,6}, vectorSub;
vectorSub = vector1-vector2;
std::cout << vectorSub << "\n";will print
{-3,-3,-3}Multiplies a Vector and a scalar
Vector<int> vector1 {1,2,3}, vectorMultiplied;
int scalar = 5;
vectorMultiplied = vector1 * scalar;
std::cout << vectorMultiplied << "\n";will print
{5,10,15}Defines a class called LinearSystem. Its only method is solve(), that returns a Vector with the solutions of the system.
// creating the system
std::vector<Vector<double>> system = {{1,1,1,1}, {0,1,2,1}, {0,0,1,1}};
/*
1x + 1y + 1z = 1
0x + 1y + 2z = 1
0x + 0y + 1z = 1
*/
// solving the linear system
LinearSystem ls(system);
Vector<double> solution = ls.solve();
std::cout << solution << "\n";will print
{1,-1,1}The program will not work if the linear system contains 0 in any position of the "main diagonal".
Maybe you'll need to change the order of the lines.
{{0,1,2}, {1,3,7}} wont work, but {{1,3,7}, {0,1,2}} will.
Try writing the matrix in a paper without the last column if the solutions keep returning "nan", it will help you see where is the 0 in the main diagonal.
Wont work \ Will work
0 1 1 3
1 3 0 1
If you try to sum or subtract two Vector with different sizes, the final size will be the same as the First vector. Other columns wont be modified.
Vector<double> vector1 {1,2,3}, vector2 {10,20}, vector12, vector21;
vector12 = vector1 + vector2;
vector21 = vector2 + vector1;
std::cout << vector12 << " " << vector21 << "\n";will print
{11,22,3} {11,22}