/monty

Primary LanguageC

0x19. C - Stacks, Queues - LIFO, FIFO C Group project Algorithm Data structure ##Tests##

  1. push, pall mandatory Implement the push and pall opcodes. The push opcode

The opcode push pushes an element to the stack.

Usage: push where is an integer if is not an integer or if there is no argument given to push, print the error message L<line_number>: usage: push integer, followed by a new line, and exit with the status EXIT_FAILURE where is the line number in the file You won’t have to deal with overflows. Use the atoi function The pall opcode

The opcode pall prints all the values on the stack, starting from the top of the stack.

Usage pall Format: see example If the stack is empty, don’t print anything

  1. pint mandatory Implement the pint opcode. The pint opcode

The opcode pint prints the value at the top of the stack, followed by a new line.

Usage: pint If the stack is empty, print the error message L<line_number>: can't pint, stack empty, followed by a new line, and exit with the status EXIT_FAILURE

  1. pop mandatory Implement the pop opcode. The pop opcode

The opcode pop removes the top element of the stack.

Usage: pop If the stack is empty, print the error message L<line_number>: can't pop an empty stack, followed by a new line, and exit with the status EXIT_FAILURE

  1. swap mandatory Implement the swap opcode. The swap opcode

The opcode swap swaps the top two elements of the stack.

Usage: swap If the stack contains less than two elements, print the error message L<line_number>: can't swap, stack too short, followed by a new line, and exit with the status EXIT_FAILURE

  1. add mandatory Implement the add opcode. The add opcode

The opcode add adds the top two elements of the stack.

Usage: add If the stack contains less than two elements, print the error message L<line_number>: can't add, stack too short, followed by a new line, and exit with the status EXIT_FAILURE The result is stored in the second top element of the stack, and the top element is removed, so that at the end: The top element of the stack contains the result The stack is one element shorter

  1. nop mandatory Implement the nop opcode. The nop opcode

The opcode nop doesn’t do anything.

Usage: nop

  1. sub #advanced Implement the sub opcode. The sub opcode

The opcode sub subtracts the top element of the stack from the second top element of the stack.

Usage: sub If the stack contains less than two elements, print the error message L<line_number>: can't sub, stack too short, followed by a new line, and exit with the status EXIT_FAILURE The result is stored in the second top element of the stack, and the top element is removed, so that at the end: The top element of the stack contains the result The stack is one element shorter

  1. div #advanced Implement the div opcode. The div opcode

The opcode div divides the second top element of the stack by the top element of the stack.

Usage: div If the stack contains less than two elements, print the error message L<line_number>: can't div, stack too short, followed by a new line, and exit with the status EXIT_FAILURE The result is stored in the second top element of the stack, and the top element is removed, so that at the end: The top element of the stack contains the result The stack is one element shorter If the top element of the stack is 0, print the error message L<line_number>: division by zero, followed by a new line, and exit with the status EXIT_FAILURE

  1. mul #advanced Implement the mul opcode. The mul opcode

The opcode mul multiplies the second top element of the stack with the top element of the stack.

Usage: mul If the stack contains less than two elements, print the error message L<line_number>: can't mul, stack too short, followed by a new line, and exit with the status EXIT_FAILURE The result is stored in the second top element of the stack, and the top element is removed, so that at the end: The top element of the stack contains the result The stack is one element shorter

  1. mod #advanced Implement the mod opcode. The mod opcode

The opcode mod computes the rest of the division of the second top element of the stack by the top element of the stack.

Usage: mod If the stack contains less than two elements, print the error message L<line_number>: can't mod, stack too short, followed by a new line, and exit with the status EXIT_FAILURE The result is stored in the second top element of the stack, and the top element is removed, so that at the end: The top element of the stack contains the result The stack is one element shorter If the top element of the stack is 0, print the error message L<line_number>: division by zero, followed by a new line, and exit with the status EXIT_FAILURE

  1. comments #advanced Every good language comes with the capability of commenting. When the first non-space character of a line is #, treat this line as a comment (don’t do anything).

  2. pchar #advanced Implement the pchar opcode. The pchar opcode

The opcode pchar prints the char at the top of the stack, followed by a new line.

Usage: pchar The integer stored at the top of the stack is treated as the ascii value of the character to be printed If the value is not in the ascii table (man ascii) print the error message L<line_number>: can't pchar, value out of range, followed by a new line, and exit with the status EXIT_FAILURE If the stack is empty, print the error message L<line_number>: can't pchar, stack empty, followed by a new line, and exit with the status EXIT_FAILURE

  1. pstr #advanced Implement the pstr opcode. The pstr opcode

The opcode pstr prints the string starting at the top of the stack, followed by a new line.

Usage: pstr The integer stored in each element of the stack is treated as the ascii value of the character to be printed The string stops when either: the stack is over the value of the element is 0 the value of the element is not in the ascii table If the stack is empty, print only a new line.

  1. rotl #advanced Implement the rotl opcode. The rotl opcode

The opcode rotl rotates the stack to the top.

Usage: rotl The top element of the stack becomes the last one, and the second top element of the stack becomes the first one rotl never fails

  1. rotr #advanced Implement the rotr opcode. The rotr opcode

The opcode rotr rotates the stack to the bottom.

Usage: rotr The last element of the stack becomes the top element of the stack rotr never fails

  1. stack, queue #advanced Implement the stack and queue opcodes. The stack opcode

The opcode stack sets the format of the data to a stack (LIFO). This is the default behavior of the program.

Usage: stack The queue opcode

The opcode queue sets the format of the data to a queue (FIFO).

Usage: queue When switching mode:

The top of the stack becomes the front of the queue The front of the queue becomes the top of the stack

  1. Brainfck #advanced Write a Brainfck script that prints School, followed by a new line. All your Brainfck files should be stored inside the bf sub directory You can install the bf interpreter to test your code: sudo apt-get install bf Read: Brainfck

  2. Add two digits #advanced Add two digits given by the user. Read the two digits from stdin, add them, and print the result The total of the two digits with be one digit-long (<10)

  3. Multiplication #advanced Multiply two digits given by the user. Read the two digits from stdin, multiply them, and print the result The result of the multiplication will be one digit-long (<10)

  4. Multiplication level up #advanced Multiply two digits given by the user. Read the two digits from stdin, multiply them, and print the result, followed by a new line