django-jsonview
django-jsonview is a simple decorator that translates Python objects to JSON and makes sure your view will always return JSON.
I've copied and pasted this so often I decided I just wanted to put it in a package.
Installation
Just install with pip
:
pip install django-jsonview
No need to add to INSTALLED_APPS
or anything.
Usage
Just import the decorator, use, and return a JSON-serializable object:
from jsonview.decorators import json_view @json_view def my_view(request): return { 'foo': 'bar', }
Content Types
If you need to return a content type other than the standard
application/json
, you can specify that in the decorator with the
content_type
argument, for example:
from jsonview.decorators import json_view @json_view(content_type='application/vnd.github+json') def myview(request): return {'foo': 'bar'}
The response will have the appropriate content type header.
Return Values
The default case is to serialize your return value and respond with HTTP
200 and a Content-Type of application/json
.
The @json_view
decorator will handle many exceptions and other
cases, including:
Http404
PermissionDenied
HttpResponseNotAllowed
(e.g.require_GET
,require_POST
)jsonview.exceptions.BadRequest
(see below)- Any other exception (logged to
django.request
).
Any of these exceptions will return the correct status code (i.e., 404,
403, 405, 400, 500) a Content-Type of application/json
, and a
response body that looks like:
json.dumps({ 'error': STATUS_CODE, 'message': str(exception), })
Note
As of v0.4, application exceptions do not behave this way if
DEBUG = False
. When DEBUG = False
, the message
value is
always An error occurred
. When DEBUG = True
, the exception
message is sent back.
BadRequest
HTTP does not have a great status code for "you submitted a form that didn't validate," and so Django doesn't support it very well. Most examples just return 200 OK.
Normally, this is fine. But if you're submitting a form via Ajax, it's nice to have a distinct status for "OK" and "Nope." The HTTP 400 Bad Request response is the fallback for issues with a request not-otherwise-specified, so let's do that.
To cause @json_view
to return a 400, just raise a
jsonview.exceptions.BadRequest
with whatever appropriate error
message.
Exceptions
If your view raises an exception, @json_view
will catch the
exception, log it to the normal django.request
logger, and return a
JSON response with a status of 500 and a body that looks like the
exceptions in the Return Values section.
Note
Because the @json_view
decorator handles the exception instead of
propagating it, any exception middleware will not be called, and
any response middleware will be called.
Status Codes
If you need to return a different HTTP status code, just return two values instead of one. The first is your serializable object, the second is the integer status code:
@json_view def myview(request): if not request.user.is_subscribed(): # Send a 402 Payment Required status. return {'subscribed': False}, 402 # Send a 200 OK. return {'subscribed': True}
Extra Headers
You can add custom headers to the response by returning a tuple of three values: an object, a status code, and a dictionary of headers.
@json_view def myview(request): return {}, 200, {'X-Server': 'myserver'}
Custom header values may be overwritten by response middleware.
Raw Return Values
To make it possible to cache JSON responses as strings (and because they
aren't JSON serializable anyway) if you return an HttpResponse
object (or subclass) it will be passed through unchanged, e.g.:
from django import http from jsonview.decorators import JSON @json_view def caching_view(request): kached = cache.get('cache-key') if kached: return http.HttpResponse(kached, content_type=JSON) # Assuming something else populates this cache. return {'complicated': 'object'}
Note
@require_POST
and the other HTTP method decorators work by
returning a response, rather than raising, an an exception, so
HttpResponseNotAllowed
is handled specially.
Alternative JSON Implementations
There is a healthy collection of JSON parsing and generating libraries
out there. By default, it will use the old standby, the stdlib json
module. But, if you'd rather use ujson, or cjson or yajl, you should
go for it. Just add this to your Django settings:
JSON_MODULE = 'ujson'
Anything, as long as it's a module that has .loads()
and .dumps()
methods.
By default, @json_view
uses Django's DjangoJSONSerializer
class.
If the JSON module you're using does not support the cls
kwarg, use
the following setting to not set a serializer:
JSON_USE_DJANGO_SERIALIZER = False
Note
Without the Django serializer, datetime.datetime
objects will not
be automatically serializable.
Contributing
Pull requests and issues welcome! I ask two simple things:
- Tests, including the new ones you added, must pass. (See below.)
- The
flake8
tool should not return any issues.
Running Tests
To run the tests, you probably want to create a virtualenv, then
install Django and Mock with pip
:
pip install Django==${DJANGO_VERSION} mock==1.0.1
Then run the tests with:
./run.sh test