You can join this assignment, here. It is due Wednesday October 11 at 1:30am.
There is a 'skeleton' for each of these, in the assignment that you've checked out.
The answers are also there, so that you can check your work.
Fill your code into the existing files, as indicated.
You can run ./hw2_test.py
to check the whole thing.
If everything passes, commit your code (git add, commit, push).
Check your repository online to see that the push was successful.
Remember that you will be graded on correctness, style, and commenting.
When you are done, go to Canvas and take the very short quiz. You will have to make small modifications of your code on the fly.
Important: please commit the version of the code without the modifications used for the quiz. In other words, change it back, or commit before the quiz!
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Find the 9th positive integer that is a multiple of 4, 13, 14, 26, and 50.
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Fibonacci numbers are defined by adding the previous two terms. Starting with 1 and 1, that gives 1, 1, 2, 3, 5, 8, etc. Find the sum of all Fibonnacci numbers divisible by 17 and below 1 billion. (
while
andif
, and%
) -
The number 175832868806 has no prime factors above 300. Count the unique prime factors. (Hint: first make a list of all the primes up to 300. How would you express a prime in python?)
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There is a 1000-digit number, below. If you multiply five consecutive digits, the largest value you can find is 9 × 5 × 9 × 9 × 9 = 32805. Multiplying 12 consecutive digits, what is the largest product you can find?
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Pythagorean triples have the property a² + b² = c². For instance the familiar 3, 4, 5 triangle has 3² + 4² = 9 + 16 = 25 = 5². There is one pythagorean triple for which a + b + c = 1000. Find the product a × b × c.
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Challenge: In the 2×2 grid shown below, the shortest path between two opposite corners is four units long. There are six options for such a path (see below). For a 100×100 grid, the shortest path is 200 units long. How many such paths are there?
Hints: What is necessary for a path to be a "shortest path"? Alternative hint: useimport math
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Challenge: A Collatz sequence is defined by:
- n → n/2 (for even n)
- n → 3n + 1 (for odd n) Using this rule, for 13, we get: 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1. Successive links in a Collatz sequence can be expressed in python by the function,
def collatz(n): if n%2: return 3*n + 1 else: return int(n/2) link = collatz(link)
It is believed that the sequence ends at 1, for all numbers. What is the longest Collatz sequence that starts below 2 million?
Double bonus: Use precomputation and recursive functional calls.
Here is the 1000-digit number, for exercise 4.
1334689116556462941882035808943573171674164401363769460864490234588978262666944913475783756741523897
2451842078794008017729485191070221721127038509952508280176431149895323416382564339029748626819508699
0955072496443867036500559413877056832798700698818111509823878655934307473221647215004911386585940003
6834001396323915862736324118712200726467082136557785333250304970064033489578066450615899117582800671
4920068918928063049564469657907330954702349255539722752209584079902759262004445958585816812757463180
8959993123839057795949253567061245191709785620427993669881880847373417906939397055918030430330169483
5535657388574351479006304909345090039619401560275818621377887855535660203417104398980782823962234208
2472624521308758843193838529317281058585486047922915733289925592867620144082168498632352326188791465
7015627819301645817526587333877541158580040204764914823925333504663643182191948572526248328737405212
1386952248950622806575169311906365131300057110279941542555942008569206742619537842879039448112019071