RSA Factoring Challenge
Before you continue reading, start this song in the background :)
We have sniffed an unsecured network and found numbers that are used to encrypt very important documents. It seems that those numbers are not always generated using large enough prime numbers. Your mission should you choose to accept it, is to factorize these numbers as fast as possible before the target fixes this bug on their server - so that we can decode the encrypted documents.
Read or watch:
RSA => https://en.wikipedia.org/wiki/RSA_(cryptosystem%29
How does HTTPS provide security? => https://stackoverflow.com/questions/3968095/how-does-https-provide-security
Prime Factorization => https://privacycanada.net/mathematics/prime-factorization/
Why RSA? => https://jaredatandi.hashnode.dev/rsa-factoring
=> You can choose the language of your choice. => OS needs to be Standard Ubuntu 20.04 LTS/
Factorize as many numbers as possible into a product of two smaller numbers.
Usage: factors where is a file containing natural numbers to factor. One number per line You can assume that all lines will be valid natural numbers greater than 1 You can assume that there will be no empty line and no space before and after the valid number The file will always end with a new line Output format: n=p*q one factorization per line p and q don’t have to be prime numbers
See example
You can work on the numbers of the file in the order of your choice
Your program should run without any dependency: You will not be able to install anything on the machine we will run your program on
Time limit: Your program will be killed after 5 seconds if it hasn’t finished
Push all your scripts, source code, etc… to your repository
we will only run your executable factors
julien@ubuntu:/factors$ cat tests/test00
4
12
34
128
1024
4958
1718944270642558716715
9
99
999
9999
9797973
49
239809320265259
julien@ubuntu:/factors$ time ./factors tests/test00
4=22
12=62
34=172
128=642
1024=5122
4958=24792
1718944270642558716715=3437888541285117433435
9=33
99=333
999=3333
9999=33333
9797973=32659913
49=77
239809320265259=1548578315485773
real 0m0.009s user 0m0.008s sys 0m0.001s julien@ubuntu:~/factors$
RSA Laboratories states that: for each RSA number n, there exist prime numbers p and q such that
n = p × q. The problem is to find these two primes, given only n.
This task is the same as task 0, except:
p and q are always prime numbers There is only one number in the files How far can you go in less than 5 seconds?
Read: RSA Factoring Challenge
julien@ubuntu:/RSA Factoring Challenge$ cat tests/rsa-1
6
julien@ubuntu:/RSA Factoring Challenge$ ./rsa tests/rsa-1
6=32
julien@ubuntu:/RSA Factoring Challenge$ cat tests/rsa-2
77
julien@ubuntu:/RSA Factoring Challenge$ ./rsa tests/rsa-2
77=117
julien@ubuntu:/RSA Factoring Challenge$ [...]/RSA Factoring Challenge$ cat tests/rsa-15
239821585064027
julien@ubuntu:
julien@ubuntu:/RSA Factoring Challenge$ ./rsa tests/rsa-15
239821585064027=15486481*15485867
julien@ubuntu:/RSA Factoring Challenge$ cat tests/rsa-16
2497885147362973
julien@ubuntu:~/RSA Factoring Challenge$ ./rsa tests/rsa-16
2497885147362973=49979141*49978553