harvardprogomar
precision = 10 i = 2/5 for n in range(precision): i = (1/i) + 2 sqrt2 = (1/i) + 1 precision = 200 a = (1 - (sqrt2/2) -((sqrt2/2)* I)) for n in range(2, p
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precision = 10 i = 2/5 for n in range(precision): i = (1/i) + 2 sqrt2 = (1/i) + 1 precision = 200 a = (1 - (sqrt2/2) -((sqrt2/2)* I)) for n in range(2, p
harvardprogomar doesn’t have any stars yet.