intervaltree

A mutable, self-balancing interval tree for Python 2 and 3. Queries may be by point, by range overlap, or by range envelopment.

This library was designed to allow tagging text and time intervals, where the intervals include the lower bound but not the upper bound.

Installing

pip install intervaltree

Features

Supports Python 2.7 and Python 3.4+ (Tested under 2.7, and 3.4 thru 3.6)
Initializing
- blank tree = IntervalTree()
- from an iterable of Interval objects (tree = IntervalTree(intervals))
- from an iterable of tuples (tree = IntervalTree.from_tuples(interval_tuples))
Insertions
- tree[begin:end] = data
- tree.add(interval)
- tree.addi(begin, end, data)
Deletions
- tree.remove(interval) (raises ValueError if not present)
- tree.discard(interval) (quiet if not present)
- tree.removei(begin, end, data) (short for tree.remove(Interval(begin, end, data)))
- tree.discardi(begin, end, data) (short for tree.discard(Interval(begin, end, data)))
- tree.remove_overlap(point)
- tree.remove_overlap(begin, end) (removes all overlapping the range)
- tree.remove_envelop(begin, end) (removes all enveloped in the range)
Overlap queries
- tree[point]
- tree[begin:end]
- tree.search(point)
- tree.search(begin, end)
Envelop queries
- tree.search(begin, end, strict=True)
Membership queries
- interval_obj in tree (this is fastest, O(1))
- tree.containsi(begin, end, data)
- tree.overlaps(point)
- tree.overlaps(begin, end)
Iterable
- for interval_obj in tree:
- tree.items()
Sizing
- len(tree)
- tree.is_empty()
- not tree
- tree.begin() (the begin coordinate of the leftmost interval)
- tree.end() (the end coordinate of the rightmost interval)
Set-like operations
- union
  - result_tree = tree.union(iterable)
  - result_tree = tree1 | tree2
  - tree.update(iterable)
  - tree |= other_tree
- difference
  - result_tree = tree.difference(iterable)
  - result_tree = tree1 - tree2
  - tree.difference_update(iterable)
  - tree -= other_tree
- intersection
  - result_tree = tree.intersection(iterable)
  - result_tree = tree1 & tree2
  - tree.intersection_update(iterable)
  - tree &= other_tree
- symmetric difference
  - result_tree = tree.symmetric_difference(iterable)
  - result_tree = tree1 ^ tree2
  - tree.symmetric_difference_update(iterable)
  - tree ^= other_tree
- comparison
  - tree1.issubset(tree2) or tree1 <= tree2
  - tree1 <= tree2
  - tree1.issuperset(tree2) or tree1 > tree2
  - tree1 >= tree2
  - tree1 == tree2
Restructuring
- chop(begin, end) (slice intervals and remove everything between begin and end, optionally modifying the data fields of the chopped-up intervals)
- slice(point) (slice intervals at point)
- split_overlaps() (slice at all interval boundaries, optionally modifying the data field)
- merge_overlaps() (joins overlapping intervals into a single interval, optionally merging the data fields)
- merge_equals() (joins intervals with matching ranges into a single interval, optionally merging the data fields)
Copying and typecasting
- IntervalTree(tree) (Interval objects are same as those in tree)
- tree.copy() (Interval objects are shallow copies of those in tree)
- set(tree) (can later be fed into IntervalTree())
- list(tree) (ditto)
Pickle-friendly
Automatic AVL balancing

Examples

Getting started

>>> from intervaltree import Interval, IntervalTree
>>> t = IntervalTree()
>>> t
IntervalTree()

Adding intervals - any object works!

>>> t[1:2] = "1-2"
>>> t[4:7] = (4, 7)
>>> t[5:9] = {5: 9}

Query by point

The result of a query is a set object, so if ordering is important, you must sort it first.

>>> sorted(t[6])
[Interval(4, 7, (4, 7)), Interval(5, 9, {5: 9})]
>>> sorted(t[6])[0]
Interval(4, 7, (4, 7))

Query by range

Note that ranges are inclusive of the lower limit, but non-inclusive of the upper limit. So:
```
>>> sorted(t[2:4])
[]
```
But:
```
>>> sorted(t[1:5])
[Interval(1, 2, '1-2'), Interval(4, 7, (4, 7))]
```

Accessing an Interval object

>>> iv = Interval(4, 7, (4, 7))
>>> iv.begin
4
>>> iv.end
7
>>> iv.data
(4, 7)

>>> begin, end, data = iv
>>> begin
4
>>> end
7
>>> data
(4, 7)

Constructing from lists of intervals

We could have made a similar tree this way:

>>> ivs = [(1, 2), (4, 7), (5, 9)]
>>> t = IntervalTree(
...    Interval(begin, end, "%d-%d" % (begin, end)) for begin, end in ivs
... )

Or, if we don't need the data fields:

>>> t2 = IntervalTree(Interval(*iv) for iv in ivs)

Or even:

>>> t2 = IntervalTree.from_tuples(ivs)

Removing intervals

>>> t.remove( Interval(1, 2, "1-2") )
>>> sorted(t)
[Interval(4, 7, '4-7'), Interval(5, 9, '5-9')]

>>> t.remove( Interval(500, 1000, "Doesn't exist"))  # raises ValueError
Traceback (most recent call last):
ValueError

>>> t.discard(Interval(500, 1000, "Doesn't exist"))  # quietly does nothing

>>> del t[5]  # same as t.remove_overlap(5)
>>> t
IntervalTree()

We could also empty a tree entirely:

>>> t2.clear()
>>> t2
IntervalTree()

Or remove intervals that overlap a range:

>>> t = IntervalTree([
...     Interval(0, 10),
...     Interval(10, 20),
...     Interval(20, 30),
...     Interval(30, 40)])
>>> t.remove_overlap(25, 35)
>>> sorted(t)
[Interval(0, 10), Interval(10, 20)]

We can also remove only those intervals completely enveloped in a range:

>>> t.remove_envelop(5, 20)
>>> sorted(t)
[Interval(0, 10)]

Chopping

We could also chop out parts of the tree:

>>> t = IntervalTree([Interval(0, 10)])
>>> t.chop(3, 7)
>>> sorted(t)
[Interval(0, 3), Interval(7, 10)]

To modify the new intervals' data fields based on which side of the interval is being chopped:

>>> def datafunc(iv, islower):
...     oldlimit = iv[islower]
...     return "oldlimit: {0}, islower: {1}".format(oldlimit, islower)
>>> t = IntervalTree([Interval(0, 10)])
>>> t.chop(3, 7, datafunc)
>>> sorted(t)[0]
Interval(0, 3, 'oldlimit: 10, islower: True')
>>> sorted(t)[1]
Interval(7, 10, 'oldlimit: 0, islower: False')

Slicing

You can also slice intervals in the tree without removing them:

>>> t = IntervalTree([Interval(0, 10), Interval(5, 15)])
>>> t.slice(3)
>>> sorted(t)
[Interval(0, 3), Interval(3, 10), Interval(5, 15)]

You can also set the data fields, for example, re-using datafunc() from above:

>>> t = IntervalTree([Interval(5, 15)])
>>> t.slice(10, datafunc)
>>> sorted(t)[0]
Interval(5, 10, 'oldlimit: 15, islower: True')
>>> sorted(t)[1]
Interval(10, 15, 'oldlimit: 5, islower: False')

Future improvements

See the issue tracker on GitHub.

Based on

Eternally Confuzzled's AVL tree
Wikipedia's Interval Tree
Heavily modified from Tyler Kahn's Interval Tree implementation in Python (GitHub project)
Incorporates contributions from:
- konstantint/Konstantin Tretyakov of the University of Tartu (Estonia)
- siniG/Avi Gabay
- lmcarril/Luis M. Carril of the Karlsruhe Institute for Technology (Germany)

Copyright

Chaim-Leib Halbert, 2013-2017
Modifications, Konstantin Tretyakov, 2014

Licensed under the Apache License, version 2.0.

The source code for this project is at https://github.com/chaimleib/intervaltree