Algorithm for find an array which includes array of all anagram.
// Grouping of an Anagram
// const input = findGroupsOfAnagram(["bag", "gab", "foo", "abg", "oof", "ofo"]);
// // Output
// [ ["bag", "gab", "abg"], ["foo", "oof", "ofo"] ];
let arr = ["bag", "gab", "foo", "abg", "oof", "ofo"];
console.log(checkAnagram(arr));
Answer :-1
// function checkAnagram(inp) {
// let res = [];
// for (let i = 0; i < inp.length; i++) {
// res.push([inp[i]]);
// let arr1 = inp[i].split("").sort().join("");
// for (let j = i + 1; j < inp.length; j++) {
// let arr2 = inp[j].split("").sort().join("");
// if (arr1 === arr2) {
// res[i].push(inp[j]);
// inp.splice(j,1)
// j=j-1
// }
// }
// }
// return res
// }
function checkAnagram(arr) {
let res = [];
let obj = {};
for (let i = 0; i < arr.length; i++) {
let temp1 = [arr[i]];
let str1 = arr[i].split("").sort().join("");
if (obj.hasOwnProperty(str1)) {
continue;
}
obj[str1] = true;
for (let j = i + 1; j < arr.length; j++) {
let str2 = arr[j].split("").sort().join("");
if (str2 === str1) {
temp1.push(arr[j]);
}
}
res.push(temp1);
}
return res;
}