markjprice/cs12dotnet8

CS 12 .Net 8 page 148

servbot007 opened this issue · 4 comments

servbot007 commented

In the section "How negative numbers are represented in binary", the last three WriteLine statements are missing the extra int.MaxValue, i, and int.MinValue respectively in their argument lists.

Easy fix but noticed this wasn't on the errata page.

markjprice commented

The code statement:

WriteLine("{0,12} {1,34}", "Decimal", "Binary");

Outputs the headers for the table:

        Decimal      Binary

The statement:

WriteLine("{0,12} {0,34:B32}", int.MaxValue);

Note that both interpolated values are for argument 0 i.e. {0,12} and {0,34:B32} so you don't need to pass the argument in twice. I suspect this is what you're missing.

Outputs the first row for the maximum value only in both decimal notation and binary notation:

2147483647 01111111111111111111111111111111

The loop:

for (int i = 8; i >= -8; i--)
{
  WriteLine("{0,12} {0,34:B32}", i);
}

Outputs the values between 8 and -8 in both decimal notation and binary notation:

        8 00000000000000000000000000001000
        7 00000000000000000000000000000111
        6 00000000000000000000000000000110
        5 00000000000000000000000000000101
        4 00000000000000000000000000000100
        3 00000000000000000000000000000011
        2 00000000000000000000000000000010
        1 00000000000000000000000000000001
        0 00000000000000000000000000000000
       -1 11111111111111111111111111111111
       -2 11111111111111111111111111111110
       -3 11111111111111111111111111111101
       -4 11111111111111111111111111111100
       -5 11111111111111111111111111111011
       -6 11111111111111111111111111111010
       -7 11111111111111111111111111111001
       -8 11111111111111111111111111111000

And the final statement:

WriteLine("{0,12} {0,34:B32}", int.MinValue);

Outputs the minimum value in both decimal notation and binary notation:

-2147483648 10000000000000000000000000000000
servbot007 commented