//1. Write a while
loop and a for
loop that takes the variable "num" and logs all the numbers, descending, between "num" and 1.
//while loop:
let num = 13
while(num >= 1){ console.log("the number is " + num) num-- }
//for loop: let i = 13 for(i = 13; i >= 1; i -= 1) { console.log(i) }
//2. Write a while
loop and a for
loop that takes the variable "num", and iterates over all numbers from 0 to "num".
//For each iteration, it will check if the current number is even or odd, and log that to the screen (e.g. "2 is even")
//while loop:
let num = 0;
while(num <= 33 ){ if(num % 2 === 0){ console.log(num + " is even") } if (num % 2 !== 0) { console.log(num + " is odd") } num++ }
//for loop:
for( i = 0; i <= 33; i++){ if(i % 2 === 0){ console.log(i + " is even") } if (i % 2 !== 0) { console.log(i + " is odd") } }
- //Write a
while
loop and afor
loop that takes the variable "num" and iterates over all numbers from 0 to "num". //For each iteration of the loop, it will multiply the number by 9 and log the result (e.g. "2 * 9 = 18").
for(i = 0; i <= 15; i++){ console.log(i + " * 9 = " + i * 9) }
//4. Write a loop that uses console.log to log all the numbers from 1 to 100, with two exceptions. For numbers divisible by 3, log "Fizz" instead of the number, and for numbers divisible by 5 (and not 3), log "Buzz" instead.
for(i = 0; i <= 100; i++) { if(i % 3 === 0) { console.log("Fizz") } else if (i % 5 === 0) { console.log("Buzz") } else { console.log(i) } }
//5. Modify your program to log "FizzBuzz", for numbers that are divisible by both 3 and 5 (still log "Fizz" or "Buzz" for numbers divisible by only one of those).
for(i = 0; i <= 100; i++) { if (i % 3 === 0 && i % 5 === 0 ) { console.log("FuzzBuzz") } else if(i % 3 === 0) { console.log("Fizz") } else if (i % 5 === 0) { console.log("Buzz") } else { console.log(i) } }
// Bonus: // // 1. Write a program that would log the lyrics of the song 99 Bottles of Beer. This is the first verse of the song: // // 99 bottles of beer on the wall, // // 99 bottles of beer. // // Take one down, pass it around, // // 98 bottles of beer on the wall. // // This verse is repeated, each time with one less bottle, until the number of bottles is 0. When the number of bottles is 2, the verse is: // // 2 bottles of beer on the wall, // // 2 bottles of beer. // // Take one down, pass it around, // // 1 bottle of beer on the wall. // // In the last line, the word bottles (plural), is replaced with bottle (singular) // // When the number of bottles is 1, the verse is: // // 1 bottle of beer on the wall, // // 1 bottle of beer. // // Take one down, pass it around, // // No more bottle of beer on the wall.
let bNum = 99;
while(bNum > 0) {
if(bNum > 1) { console.log(bNum + " bottles of beer on the wall, "+ bNum + " bottles of beer, Take one down, pass it around, " + bNum + " bottles of beer on the wall. ") } bNum = bNum - 1;
if(bNum < 2) { console.log(bNum + " bottle of beer on the wall, " + bNum + " bottle of beer, Take one down, pass it around, " + bNum + " bottle of beer on the wall. ") }
}
- Use the assignGrade function (given below). Write a function that logs each number from 60 - 100 along with its corresponding letter score. Exp For each number from 81 to 90, log B, like so:
81 - B
82 - B
83 - B
...
function assignGrade(score) {
if (score > 90) {
return 'A';
} else if (score > 80) {
return 'B';
} else if (score > 70) {
return 'C';
} else if (score > 65) {
return 'D';
} else {
return 'F';
};
};