/weiboBatchFollow

微博批量关注 (转移关注列表)

MIT LicenseMIT

微博批量关注 (转移关注列表)

好像并没有什么卵用

起因

使用方法

得到 A 账号关注列表

  1. 前往微博 H5 版首页 (https://m.weibo.cn)
  2. 登录 A 账号
  3. 右键 "检查" 打开开发者工具，复制下面的代码，粘贴到控制台，等待结果并复制
  • 关注数量较多时请耐心等待
  • 由于接口限制可能无法获得完整的关注列表
(() => {
	const follows = []
	const sleep = time => () => new Promise(resolve => setTimeout(resolve, time))
	const query = page =>
		fetch(
			`/api/container/getIndex?containerid=231093_-_selffollowed&page=${page}`, 
			{ headers: { 'X-XSRF-TOKEN': (document.cookie.match(/XSRF-TOKEN=([^;$]+)/) || [])[1] || '' } }
		) 
			.then(response => response.json())
			.then(body => {
				const { data, msg, ok } = body
				if (msg === '这里还没有内容') return Promise.reject(new Error('finish'))
				if (ok !== 1) return Promise.reject(new Error(msg))
				data.cards.forEach(group => group.card_group.forEach(card => card.user && follows.push(card.user.id)))
			})
	const polling = (page = 1) => query(page).then(sleep(1500)).then(() => polling(page + 1))

	polling()
		.catch(error => console.warn(`${error.message === 'finish' ? '获取完成' : `出错了 (${error.message})` }\n\n${JSON.stringify(follows)}`))
})()

按列表为 B 账号添加关注

  1. 前往 PC 版首页 (www.weibo.com)
  2. 退出 A 账号，登录 B 账号
  3. 右键 "检查" 打开开发者工具，复制下面的代码并填入上一步得到的列表，粘贴到控制台，等待全部关注完成

每日关注数量有上限，关注数量较多需要分批(分日)处理

(list => {
	let index = 0
	const { length } = list
	const failed = []
	const deviation = () => Math.round(Math.random() * 100)
	const sleep = time => () => new Promise(resolve => setTimeout(resolve, time))
	const follow = uid =>
		fetch(`/aj/f/followed?ajwvr=6&__rnd=${Date.now()}`, {
			method: 'POST',
			headers: { 'content-type': 'application/x-www-form-urlencoded' },
			body: `uid=${uid}&objectid=&f=1&extra=&refer_sort=&refer_flag=1005050001_&location=page_100505_home&oid=${uid}&wforce=1&nogroup=false&fnick=&refer_lflag=&refer_from=profile_headerv6&template=7&special_focus=1&isrecommend=1&is_special=0&_t=0`
		})
			.then(response => response.json())
			.then(data => {
				if (data.code === '100000')
					console.log(`${index}/${length}`, uid, data.data.fnick, '关注成功')
				else {
					console.log(`${index}/${length}`, uid, '关注失败')
					failed.push(uid)
					if (data.code === '100027') return Promise.reject(new Error('captcha is required'))
				}
			})
	const subscribe = () => index < length ? follow(list[index++]).then(sleep(4000 + deviation())).then(subscribe) : Promise.resolve()

	subscribe()
		.catch(error => console.error(`出错了 (${error.message})${list.slice(index).length ? `\n\n以下 ID 还未处理，请之后再试\n\n${JSON.stringify(list.slice(index))}` : ''}`))
		.then(() => failed.length && console.warn(`以下 ID 关注失败，请重试或手动关注\n\n${JSON.stringify(failed)}`))
})(/*上一步的结果*/)