Is propagation type SUPPORTS equivalent to no Transactional decorator?

Question

Is propagation type SUPPORTS equivalent to no Transactional decorator?

Closed this issue 5 years ago · 3 comments

Suppose I have function foo() decorated with @transactional, calling function bar(). Do we get the same behavior if bar is decorated with @transactional({ propagation: Propagation.SUPPORTS }), or not decorated at all?
It seems that way by looking at the logs of start and commit transaction, but I'm not sure this is guaranteed.

Answer 1 · 2019-12-26T10:48:16.000Z

Hi @ydinari ,

The answer is yes.
SUPPORTS means that it supports the current transaction, but will run without transaction if there is no current transaction.

Hope it helps

Answer 2 · 2019-12-26T15:15:54.000Z

Thanks!
Then is there a use case where I need to use Transaction({propagation: Propagation.SUPPORTS})?

Answer 3 · 2019-12-26T15:18:43.000Z

Basically I tried to emulate all spring options. I myself, not sure what would be the use case for that.

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On Thu, 26 Dec 2019 at 17:15 Yuval Dinari ***@***.***> wrote: Thanks! Then is there a use case where I need to use Transaction({propagation: Propagation.SUPPORTS})? — You are receiving this because you commented. Reply to this email directly, view it on GitHub <#35?email_source=notifications&email_token=AAGSOAJ6KCLO4QYLIYB5OF3Q2TDCVA5CNFSM4J7J4WM2YY3PNVWWK3TUL52HS4DFVREXG43VMVBW63LNMVXHJKTDN5WW2ZLOORPWSZGOEHVWHKI#issuecomment-569074601>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AAGSOALNQFF2G47BJTMYI53Q2TDCVANCNFSM4J7J4WMQ> .