/swift-literal-type-inference

🤔 swift-syntax extension to infer types from expressions based on literal information

Primary LanguageSwiftMIT LicenseMIT

LiteralTypeInference

swift-syntax extension to infer types from expressions based on literal information.

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Usage

Implemented as an extension of the ExprSyntaxProtocol.

The type inferred from literal information can be obtained from the inferredType property.

import SwiftSyntax
import SwiftSyntaxBuilder
import LiteralTypeInference


let expr: ExprSyntax = """
[
    "item1": [
        (1, 2.0, "3", true),
        (1.0, 2, "7", false),
        (nil, nil, nil, false)
    ],
    "item2": [],
    "item3": [
        (1, 2, "3", true)
    ]
]
"""

// Get the type of expr from the `inferredType` property
let type = expr.inferredType

print(type?.formatted().description)
// => [String: [(Double?, Double?, String?, Bool)]]

License

LiteralTypeInference is released under the MIT License. See LICENSE