acdegilmnoprstuw
such that the hash(the_string) is
930846109532517
if hash is defined by the following pseudo-code:
Int64 hash (String s) { Int64 h = 7 String letters = "acdegilmnoprstuw" for(Int32 i = 0; i < s.length; i++) { h = (h * 37 + letters.indexOf(s[i])) } return h }
For example, if we were trying to find the 7 letter string where hash(the_string) was 680131659347, the answer would be "leepadg".