lrucache
- Other Language
Result at leetcode.com
Usage
lc := lrucache.New(5)
lc.Put(4, "1")
lc.Put(1, "2")
lc.Put(2, "3")
lc.Put(3, "4")
lc.Put(4, "5")
fmt.Println("Range demo:")
i := 1
lc.Range(func(key, value interface{}) bool {
fmt.Printf("[%d] %d => %s\r\n", i, key.(int), value.(string))
i++
return true
})
fmt.Println("Get demo:")
if e, ok := lc.Get(1); ok {
fmt.Printf("%d => %s\r\n", 1, e.(string))
}
fmt.Println("Reverse iteration after Get demo:")
i = 1
for e := lc.Back(); e != nil; e = e.Prev() {
fmt.Printf("[%d] %d => %s\r\n", lc.Len()-i+1, e.Key.(int), e.Value.(string))
i++
}
lc.Delete(4)
fmt.Println("Iteration after Delete demo:")
i = 1
for e := lc.Front(); e != nil; e = e.Next() {
fmt.Printf("[%d] %d => %s\r\n", i, e.Key.(int), e.Value.(string))
i++
}
Output:
Range demo:
[1] 4 => 5
[2] 3 => 4
[3] 2 => 3
[4] 1 => 2
Get demo:
1 => 2
Reverse iteration after Get demo:
[4] 2 => 3
[3] 3 => 4
[2] 4 => 5
[1] 1 => 2
Iteration after Delete demo:
[1] 1 => 2
[2] 3 => 4
[3] 2 => 3