sqrtn

A Python pacakge to calculate sqrt(n) with very high precision. "sqrtn"" implements dramatically fast. It takes only less than 30 seconds to approximate square root of 2 with 100,000 digits. Function sqrtn2() can approximate square root of n for any positive integer. The last two or three digits may be incorrect. For seek of safety, it is better to input two or three more to guarantee precision.

Installation

pip install git+https://github.com/xliusufe/sqrtnpy.git

Usage

Syntax: sqrtn(n,prec)
- Input:
  - n: a natural number
  - prec: The a positive integer, which is the precision you want.
- Output: the square root of n, which is a string.
The corresponding R package named sqrtn can be found on github.

Example 1

from sqrtn import sqrtn

fit = sqrtn(2, 100)
print(fit)

Example 2

import sqrtn

fit = sqrtn.sqrtn(2, 100)
print(fit)

Development

This Python package is developed by Xu Liu (liu.xu@sufe.edu.cn).

Additional information

Web-based calculator --------A web-based calculator
sqrt2.md ---------- The first one hundred thousand digits of the square root of 2.
sqrt3.md ---------- The first many digits of the square root of 3.
sqrt5.md ---------- The first many digits of the square root of 5.
sqrt6.md ---------- The first many digits of the square root of 6.
sqrt7.md ---------- The first many digits of the square root of 7.
sqrt8.md ---------- The first many digits of the square root of 8.