rjc955 opened this issue a year ago · 2 comments
Typing P({X}|{Y,Z}) should create a Probability object with the representation P(X|Y,Z). Instead, it creates P(X,Y,Z).
P({X}|{Y,Z})
Probability
P(X|Y,Z)
P(X,Y,Z)
Nope, this is totally correct. You're using the bar operator between two sets, which takes the union of the sets. Then the union set XYZ is passed to the construction which makes a joint distributor over all of them
Got it, thanks very much!