Launch with file that doesn't have .frag extension
danielchasehooper opened this issue · 2 comments
we have some existing shaders in our repo that don't have the .frag
extension that we would like to view in glslviewer, is there a way to launch it from the command line without cp
ing to a tmp file with the .frag extension? When you do this you don't get hot reloading for the original file
hi @danielchasehooper! For context we use .frag
or .fs
to distinguish fragment shaders from vertex shader (.vert
or .vs
). Files with .glsl
extensions are a bit ambiguous, that's why usually you see them when they are part of libraries like on https://lygia.xyz.
Solution, you could create file pairs that include the .glsl
counter part. For example:
shader.glsl
uniform vec2 u_resolution;
uniform float u_time;
void main() {
vec4 color = vec4(0.0,0.0,0.0,1.0);
vec2 uv = gl_FragCoord.xy/u_resolution;
...
gl_FragColor = color;
}
shader.frag
#include "shader.glsl"
This way:
- you don't have duplicate files
- glslViewer can track the changes of the original
.glsl
file - the
.frag
pairs can be easily generated programatically
we don't use the glsl
extension, #include
doesn't seem to work if the file doesn't have a glsl extension
It'd be useful if glslviewer had something like a --frag
param so that you can launch it like so:
glslviewer --frag shaderFileName
and it works with any extension.