/ECMS_HEV_MATLAB_SIMULINK

Real-time Optimal Control (ECMS) of Hybrid Electric Powertrains.

Primary LanguageMATLAB

ECMS_HEV_Python_SIMULINK

Real-time Optimal Control of Hybrid Electric Powertrains Equivalent consumption minimization strategy (ECMS) Optimization of Hybrid Vehicle Fuel Consumption in Python. Run the file 'HEV_ECMS.mdl'.

Files for the optimal control of parallel hybrid configurations using Equivalent consumption minimization strategy (ECMS)

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Vehicle Model

===================== HEV_ECMS.mdl - A basic vehicle model

Problem specific scrips and functions

===================================== init_HEV_ECMS.m - Initialize data parallelhybrid_ECMS.m - Torque Split function file

(C) 2020 Ruchit Bhikadiya

  1. Main Assignment information: A hybrid vehicle has various possibilities of configurations. The parallel vehicle is the well known concepts. The parallel hybrid has a mechanical link (via transmission) from the combustion engine to the wheels. This means that for the parallel hybrid only the state of charge is optimized. The models for the parallel, should be formulated so that the cost for following an arc in the optimal control problem can be calculated.

  2. Vehicle Parameters:

    Lower Heating Value

    H_l = 44.6e6 # J/kg

    Fuel Density

    roh_l = 732.2 # Kg/m3

    Air Density

    roh_a = 1.18 # kg/m3

    Engine Inertia

    Je = 0.2 # kgm2

    Engine Maximum Torque

    T_engine_max = 115 # Nm

    Engine Displacment

    V_disp = 1.497e-3 # m3

    Willans approximation of engine efficiency and pressure

    e = 0.4 p_me0 = 0.1e6 # MPa

    Battery charging capacity

    Q_o = 6.5 # Ah

    Open circuit voltage

    Uoc = 300 # V

    Maximum dis-/charging current

    Imax = 200 # A Imin = -200 # A

    Inner resistance

    Ri = 0.65 # ohm

    Efficiency of electrical machine

    n_electricmachine = 0.9

    Gravity

    g = 9.81

    Drag coefficient

    cD = 0.32

    Rolling resistance coefficient

    cR = 0.015

    Frontal area

    Af = 2.31 # m2

    Vehicle mass

    mv = 1500 # kg

    Wheel radius

    rw = 0.3 # m

    Inertia of the wheels

    Jw = 0.6 # kgm2 mwheel = Jw / (rw ** 2)

    Efficiency of Transmission

    eta_gearbox = 0.98

    Electric machine Maximum Torque

    T_em_max = 400 # Nm

    Power of Electric Machine

    P_em_max = 50 # kW

    Electric motor weight

    m_em = 1.5 # kg/Kw

    Maximum powertrain power

    P_pt_max = 90.8 # kW